IS MOOG PRECISELY 1.0 V /OCTAVE OR SLIGHTLY MORE ?

hi,
i’d like to know if the moog CV is exactly 1.0 V/ OCTAVE or slightly more and how much exactly ?

By “Moog” I presume you mean the Voyager. It’s 0.935 V/Oct (as stated in the Voyager User Manual).


Greg

If you want resonance that tracks the keyboard accurately in perfect octaves, you could always get Little phatty… The voyager is not able to do this.

Voyager internal CV is 0.935v/oct. If you use the I/O jacks or the VX-351, it’s 1v/oct.

sorry,
i was speaking about the old ones : minimoog, micromoog, multimoog.
the only tech i could find that repair old synths in paris is telling me that’ it’s impossible my micromoog was tracking in tune when i played it with a kenton pro 2000 midi to cv, plugged in the cv gate (s trig and oscillator inputs ) if i was not using the SCALE function to compensate the voltage difference as it is not exactly 1.0 v / octave.
i don’t remember i had to use this scale compensation.

also, is it possible to have the glide of the minimoog when playing it through a midi to cv ( s trig / oscillator) ?
i still have those plugs at the back but have no wire with that kind of connector for the s trig.
i have a cv gate installed on that minimoog as well but i can’t have the glide through these ones

The micromoog tracks at slightly less than 1v/oct. Many CV interfaces have a “trim” function to address this.

Most other “old Moogs” were 1v/oct to my knowledge…