Hi,
as VCO signals have no dynamics I did not choose an aural enhancer that is based on multiband compression, which would on a static volume signal be nothing more than a wideband EQ. Also the highpassed distortion part of the aural enhancers didn’t seem appealing to me because I prefer filter distortion of the full band signal.
However, how it sounds is more important than the theory and a boosted EQ might also drive the filter a bit - but not in its full spectrum.
So I turned to just a signal amplifier to saturate the filter a bit. Which is kind of subtle because this gem has a nice bit of headroom in the filter.
As I found no electrical specification I had to measure, and as I had no scope, I measured with a multimeter (difference see explanation below).
3 OSC out at full volume on the mixer: Multimeter shows 0.4 V … 0.6 V
I thought the OSCs are running at 9V internally, but maybe that’s wrong, or the signal is converted to pedal levels.
I attached a Minifogger Boost, put it on full volume (wo expr pedal) and then measured about 1.4 V output with a multimeter.
Result (volume compensated):
- Little bit gritty saturation
- More weight (bass, not related to the Minifogger filter as far as I can tell)
The sound improvement is huge from a sound engineering point of view. But some might call it subtle. It’s more like one of this mixing magic things, and not giving full bite like driving a Minitaur for example.
So, what do we learn from the multimeter:
- The signal is instrument level, not line level, so instrument level pedals should be fine with it.
- Amplifying it by more than factor 2 did not immediately blow up my device (still struggle with which dB to use regarding U and P …)
- Amplifying by somewhere like factor 2 might give a notable, great and subtle saturation. But I didn’t doublecheck with just sending a signal through the MF Boost, maybe it’s the boost and not the possibly driven filter.
Hope this measurement helps someone.
(Difference multimeter vs. oscilloscipe: A 50 Hz sine signal can be converted to peak-to-peak voltage by dividing the measured value by 1.414 (i.e. SQR(2)). A three oscillator sawtooth wave cannot be calculated backwards this way, because of frequency damping and in some circumstances phase cancellation. However, I suppose roughly we can see that it is instrument level and a bost of more than 2.)