Why dose the lag “in” not have a white ring around it? is it an input right?
Just doing some experiments on my new XL, I don’t want to fry her!
So far the manual has been quite specific in regards to in’s and outs and not to connect ins to ins & outs to outs etc.
And exactly what is it used for?
Thought I would get more answers in the fooger forum regarding this part (Lag processor) of my XL in question.
Cheers
The white rings signify that there is a +5V on that particular jack. Not that it is an input. All the inputs are labeled INPUT. 
White rings will only be around inputs for passive voltage devices. The white ring tells you that there is a voltage available to power an expression pedal if it needs powering. The only exception to white rings being around inputs is the multiple. Of corse any jack on a multiple can be an input or output, but if you plug your expression pedal to a jack without power, your pedal won’t receive power, and therefore it won’t send a signal anyhere.
A lag processor doesn’t really need a powered jack because generally you are going to send a voltage to it anyway.
The lag processor will slow down the rise and fall times of a waveform. Plug a square wave into the lag processor, and mess around with it. You can change a square wave into a sawtooth.
On a synthesizers.com they call it a slew limiter. It produces glide or glissando.
Ahh cool! lol
Cheers Erick!
I thought the mults could only receive input from the top row (white rings) and output from the 3 jacks below? is not so then?
A mult is just a number of jacks wired together. Any one can be your input. I used to think that also, just don’t get confused which one your input is.
And only one input per mult right?
Thanks mate
YES! Do NOT use the mult as a mixer! Bad stuff happens, and no good can come of it! 
Cheers mate
So dose it change the wave form at the compression and refraction stage? just trying to visualize whats going on…
Lag into attenuator, the attenuator will change the size of the wave form that has been effected by the lag possessor, either expanding it or crushing it?
cheers
The best thing to do is try it, that’s what is fun about modular synthesis, the whole cause and effect aspect (as long as it’s not going to fry something).
If you have a square wave in which the rise/fall time is instantaneous, adding lag to the rise time will slow the rate at which the rise occurs. So it might be more like a sawtooth wave at that point, the fall is still instantaneous. It will glide to the peak, and then fall. If you add lag to the fall, it will then glide to and from the peak of the waveform.
Adding attenuation at this point will simply reduce the amplitude of the wave. Right now I’m using the CP’s LFO with a lagged rise time to the freqbox’s pitch input. I tried this, and at 12:00 there was virtually no change in pitch but the rise and fall of the waveform was unchanged.
Thank-you for asking me this question because I initially thought that Attenuation would undo the lag processing rather than change the waveform. Rather than visualizing and telling you that is what would happen, I had to try it to be sure I wasn’t giving you a wrong explanation. I might even add this change to my current program also!
Eric
An attenuator won’t boost the waveform. The attens on the Voyager will take the waveform from it’s unattenuated amount to full attenuation then will reverse the voltage, since the Attens are active. I missed this when I replied earlier.
Eric
Thanks very much Erick! this helps allot
I find if I can visualize whats going on to some some description I have a better understanding of whats going on under the hood, you hit the nail on the head!
Cheers mate 
I stared at a picture of a System 15 longingly trying to figure out how to patch the thing when I didn’t have my voyager. I think it really helped.
Actually patching it makes things a lot easier. 
Sure dose!